Irrigation water having the concentration of Na++, Ca++ and Mg++ as 20, 3 and 1 Milli equivalent per litre respectively will be classified as
A. Low sodium water
B. Medium sodium water
C. High sodium water
D. Very high sodium water
Answer: Option B
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A. Low sodium water
B. Medium sodium water
C. High sodium water
D. Very high sodium water
SAR= Na+/Root of (Mg+2)+(Ca+2)/2 so
SAR=20/Root of 1+3/2
=20/Root2
=10×Root 2
=14.14 Which is in Medium Sodium Water
Correct answer is 14.14
So acc. to SAR value 10-18 value comes under medium sodium water
1_10. Tk low sodium water
10-18tk medium sodium water
18-26high sodium water
26< very high
SAR=Na++upon((ca++)+(Na++)/2) whole to the power half=14.14 so anwser b is correct
0
20/√((3+1)/2)
=14
The given ans is wrong plz check it will be 2304
Sol. 7% per 300m
For 1200m -28%will be increase
So 1.28*1800=2304m
1-10 = low sodium water
10-18 = medium sodium water
18-26 = high sodium water
>26 = very high sodium water