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Flow Control -Java Programming MCQ Questions and Answers

Learn competitive java programming mcq questions and answers on Flow Control with easy and logical explanations. Page-6 section-1

51
Which of these access specifier must be used for class so that it can be inherited by another subclass?
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Answer & Solution
Answer: Option A
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52
Which of these is used as a default for a member of a class if no access specifier is used for it?
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Answer & Solution
Answer: Option A
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53
Which of these access specifiers must be used for main() method?
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Answer & Solution
Answer: Option B
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54
What will be the output of the following Java code?
class static_out 
{
    static int x;
static int y;
    void add(int a, int b)
    {
        x = a + b;
        y = x + b;
    }
}    
public class static_use 
{
    public static void main(String args[])
    {
        static_out obj1 = new static_out();
        static_out obj2 = new static_out();   
        int a = 2;
        obj1.add(a, a + 1);
        obj2.add(5, a);
        System.out.println(obj1.x + " " + obj2.y);     
    }
}
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Answer & Solution
Answer: Option C
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55
What will be the output of the following Java code?
class access
{
    public int x;
private int y;
    void cal(int a, int b)
    {
        x =  a + 1;
        y =  b;
    }        
}    
public class access_specifier 
{
    public static void main(String args[])
    {
        access obj = new access();   
        obj.cal(2, 3);
        System.out.println(obj.x + " " + obj.y);     
    }
}
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Answer & Solution
Answer: Option C
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56
Which of these is used to access a member of class before object of that class is created?
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Answer & Solution
Answer: Option C
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57
Which of the following statements are incorrect?
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Answer & Solution
Answer: Option C
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58
What will be the output of the following Java code?
class access
{
    public int x;
private int y;
    void cal(int a, int b)
    {
        x =  a + 1;
        y =  b;
    }   
    void print() 
    {
        System.out.println(" " + y);     
    } 
}   
public class access_specifier 
{
    public static void main(String args[])
    {
        access obj = new access();   
        obj.cal(2, 3);
        System.out.println(obj.x);
        obj.print();     
    }
}
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Answer & Solution
Answer: Option B
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