Joule-Thomson co-efficient for a perfect gas is
A. Zero
B. Positive
C. Negative
D. None of these
Answer: Option A
Solution(By Examveda Team)
For a perfect gas since, the enthalpy depends only on temperature and the joule Thomson coefficient which is ratio of temperature change to pressure change at constant enthalpy. Since for an perfect gas the enthalpy remaining constant leads to temperature constancy the joule Thomson coefficient becomes zero.Related Questions on Chemical Engineering Thermodynamics
A. Maxwell's equation
B. Thermodynamic equation of state
C. Equation of state
D. Redlich-Kwong equation of state
Henry's law is closely obeyed by a gas, when its __________ is extremely high.
A. Pressure
B. Solubility
C. Temperature
D. None of these
A. Enthalpy
B. Volume
C. Both A & B
D. Neither A nor B
Join The Discussion