$${\left[ {{{\left( {\sqrt {81} } \right)}^2}} \right]^2} = {\left( ? \right)^2}$$
A. 8
B. 9
C. 4096
D. 6561
E. None of these
Answer: Option E
Solution(By Examveda Team)
$$\eqalign{ & {\text{Let,}} \cr & {\left[ {{{\left( {\sqrt {81} } \right)}^2}} \right]^2} = {\left( x \right)^2} \cr & {\text{Then,}} \cr & \Leftrightarrow {x^2} = {\left( {81} \right)^2} \cr & \Leftrightarrow x = 81 \cr} $$Related Questions on Square Root and Cube Root
The least perfect square, which is divisible by each of 21, 36 and 66 is:
A. 213444
B. 214344
C. 214434
D. 231444
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