Let $$\left| {{\psi _0}} \right\rangle $$ denotes the ground state of the hydrogen atom. Choose the correct statement from those given below.
A. $$\left[ {{L_x},\,{L_y}} \right]\left| {{\psi _0}} \right\rangle = 0$$
B. $${J^2}\left| {{\psi _0}} \right\rangle = 0$$
C. $$\overrightarrow {\bf{L}} .\overrightarrow {\bf{S}} \left| {{\psi _0}} \right\rangle \ne 0$$
D. $$\left[ {{S_x},\,{S_y}} \right]\left| {{\psi _0}} \right\rangle = 0$$
Answer: Option A
A. In the ground state, the probability of finding the particle in the interval $$\left( {\frac{L}{4},\,\frac{{3L}}{4}} \right)$$ is half
B. In the first excited state, the probability of finding the particle in the interval $$\left( {\frac{L}{4},\,\frac{{3L}}{4}} \right)$$ is half This also holds for states with n = 4, 6, 8, . . . .
C. For an arbitrary state $$\left| \psi \right\rangle ,$$ the probability of finding the particle in the left half of the well is half
D. In the ground state, the particle has a definite momentum
A. (e-ax1 - e-ax2)
B. a(e-ax1 - e-ax2)
C. e-ax2 (e-ax1 - e-ax2)
D. None of the above

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