Let ABC be an equilateral triangle and AD perpendicular to BC. Then AB2 + BC2 + CA2 =?
A. 3AD2
B. 5AD2
C. 2AD2
D. 4AD2
Answer: Option D
A. 3AD2
B. 5AD2
C. 2AD2
D. 4AD2
Answer: Option D
A. $$\frac{{23\sqrt {21} }}{4}$$
B. $$\frac{{15\sqrt {21} }}{4}$$
C. $$\frac{{17\sqrt {21} }}{5}$$
D. $$\frac{{23\sqrt {21} }}{5}$$
In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is
A. 30°
B. 40°
C. 20°
D. 70°
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