Examveda

Let $$\left| n \right\rangle $$ and $$\left| p \right\rangle $$ denote the isospin state with $$I = \frac{1}{2},\,{I_3} = \frac{1}{2}$$   and $$I = \frac{1}{2},\,{I_3} = - \frac{1}{2}$$   of a nucleon respectively. Which one of the following two-nucleon states has $$I = 0,\,{I_3} = 0\,?$$

A. $$\frac{1}{{\sqrt 2 }}\left( {\left| {nn} \right\rangle - \left| {pp} \right\rangle } \right)$$

B. $$\frac{1}{{\sqrt 2 }}\left( {\left| {nn} \right\rangle + \left| {pp} \right\rangle } \right)$$

C. $$\frac{1}{{\sqrt 2 }}\left( {\left| {np} \right\rangle - \left| {pn} \right\rangle } \right)$$

D. $$\frac{1}{{\sqrt 2 }}\left( {\left| {np} \right\rangle + \left| {pn} \right\rangle } \right)$$

Answer: Option C


Join The Discussion

Related Questions on Nuclear and Particle Physics

The four possible configurations of neutrons in the ground state of $${}_4^9Be$$  nucleus according to the shell model, and the associated nuclear spin are listed below. Choose the correct one

A. $${\left( {{}^1{s_{1/2}}} \right)^2}{\left( {{}^1{p_{3/2}}} \right)^3};\,J = \frac{3}{2}$$

B. $${\left( {{}^1{s_{1/2}}} \right)^2}{\left( {{}^1{p_{1/2}}} \right)^2}{\left( {{}^1{p_{3/2}}} \right)^1};\,J = \frac{3}{2}$$

C. $${\left( {{}^1{s_{1/2}}} \right)^1}{\left( {{}^1{p_{3/2}}} \right)^4};\,J = \frac{1}{2}$$

D. $${\left( {{}^1{s_{1/2}}} \right)^2}{\left( {{}^1{p_{3/2}}} \right)^2}{\left( {{}^1{p_{1/2}}} \right)^1};\,J = \frac{1}{2}$$