Let n be the number of different five digit numbers, divisible by 4 with the digits 1,2,3,4,5 and 6, no digit being repeated in the number. What is the value of n?
A. 144
B. 168
C. 192
D. 200
Answer: Option C
Solution (By Examveda Team)
Test of divisibility by 4 is that the last two digits should be divisible by 4.When the last 2 digits are 12, i.e., _ _ _12=4×3×2=24 numbers
When last 2 digits are 16, there are 24 numbers
When last 2 digits are 24 there are 24 numbers
When last 2 digits are 32 there are 24 numbers
When last 2 digits are 36 there are 24 numbers
When last 2 digits are 52 there are 24 numbers
When last 2 digits are 56 there are 24 numbers
When last 2 digits are 64 there are 24 numbers
Total =8×24= 192
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