Let P(E) denote the probability of the event E. Given P(A) = 1, P(B) = $$\frac{1}{2}$$, the values of $${\text{P}}\left( {\frac{{\text{A}}}{{\text{B}}}} \right)$$ and $${\text{P}}\left( {\frac{{\text{B}}}{{\text{A}}}} \right)$$ respectively are
A. $$\frac{1}{4},\,\frac{1}{2}$$
B. $$\frac{1}{2},\,\frac{1}{4}$$
C. $$\frac{1}{2}$$, 1
D. 1, $$\frac{1}{2}$$
Answer: Option D
Related Questions on Probability and Statistics
A coin is tossed 4 times. What is the probability of getting heads exactly 3 times?
A. $$\frac{1}{4}$$
B. $$\frac{3}{8}$$
C. $$\frac{1}{2}$$
D. $$\frac{3}{4}$$
A. 1 and $$\frac{1}{3}$$
B. $$\frac{1}{3}$$ and 1
C. 1 and $$\frac{4}{3}$$
D. $$\frac{1}{3}$$ and $$\frac{4}{3}$$
A. E(XY) = E(X) E(Y)
B. Cov (X, Y) = 0
C. Var (X + Y) = Var (X) + Var (Y)
D. E(X2Y2) = (E(X))2 (E(Y))2

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