Let the least number of six digits which when divided by 4,6,10,15 leaves in each case same remainder 2 be N. The sum of digits in N is:
A. 3
B. 5
C. 4
D. 6
Answer: Option B
Solution (By Examveda Team)
LCM of 4, 6, 10, 15 = 60Least number of 6 digits = 100000
The leats number of 6 digits which is exactly divisible by 60 = 100000 + (60 – 40) = 100020
∴ Required Number = 100020 + 2 = 100022
Hence, the sum of digits = 1 + 0 + 0 + 0 + 2 + 2 = 5
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