Let ΔABC and ΔABD be on the same base AB and between the same parallels AB and CD. Then the relation between areas of triangles ABC and ABD will be

A. ΔABD = $$\frac{1}{3}$$ ΔABC

B. ΔABD = $$\frac{1}{2}$$ ΔABC

C. ΔABC = $$\frac{1}{2}$$ ΔABD

D. ΔABC = ΔABD

Answer: Option D

Solution (By Examveda Team)

The height of ΔABC and ΔABD are same and have same base.
∴ Area ΔABC = Area ΔABD