Let x = root 6 of 27 - sqrt 6 frac...

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Let x = $$\root 6 \of {27} - \sqrt {6\frac{3}{4}} $$ and y = $$\frac{{\sqrt {45} + \sqrt {605} + \sqrt {245} }}{{\sqrt {80} + \sqrt {125} }},$$ then the value of x² + y² is:

A. $$\frac{{223}}{{36}}$$

B. $$\frac{{221}}{{36}}$$

C. $$\frac{{221}}{9}$$

D. $$\frac{{227}}{9}$$

Answer: Option A

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