Let X1 and X2 be two independent exponentially distributed random variables with means 0.5 and 0.25 respectively. Then Y = min (X1, X2) is
A. exponentially distributed with mean $$\frac{1}{6}$$
B. exponentially distributed with mean 2
C. normally distributed with mean $$\frac{3}{4}$$
D. normally distributed with mean $$\frac{1}{6}$$
Answer: Option A

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