Mandi in Himachal Pradesh and Sindhudurg in Maharashtra have emerged the cleanest districts in India according Gramin Swachh Survekshan.
Sindhudurg was judged as the cleanest in the ‘Plains’ category and Mandi in the cleanest district in ‘Hills’ category.
The Gramin Swachh Survekshan report was released by the Union Ministry of Drinking Water and Sanitation, Rural Development and Panchayati Raj.
Overall Rankings in Swachh Survekshan Gramin
Hills category
Rank 1: Mandi (Himachal Pradesh) with 98.4 score.
Rank 2: West Sikkim (Sikkim) with 96.4 score.
Rank 3: Shimla (Himachal Pradesh) with 94.1 score.
Plains category
Rank 1: Sindhudurg (Maharashtra) with 96.8 score.
Rank 2: Nadia (West Bengal) with 95.0 score.
Rank 3: Satara (Maharashtra) with 92.9 score.
Key Points
In the survey total of 22 hill districts and 53 plain areas were assessed by the Quality Council of India (QCI).
QCI was given task to carry out the assessment by the Union Ministry of Drinking Water and Sanitation, Rural Development and Panchayati Raj A total of 22 hill districts and 53 plain areas were assessed by QCI under the Gramin Swachh Survekshan launched in May 2016.
Each district was judged on four distinct parameters of Gramin Swachh Survekshan. Maximum weightage was placed on accessibility to safe toilets and water.
The parameters to judge sanitation status included: (i) Households having access to safe toilets and using them.
It was given 40% weightage and included survey of toilet usage, water accessibility, safe disposal of waste. (ii) Households having no litter around. It was given weightage of 30%. (iii) Public places with no litter in the surrounding. It was given weightage of 10%. (iv) Households having no stagnant wastewater around. It was given weightage of 20%.
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