Match List-I with List-II and select the correct answer:
| List-I | List-II |
| a. Orthotropous ovule | 1. The ovule is completely inverted in its orientation due to approximately 180° curvature of the funiculus |
| b. Anatropous ovule | 2. The ovule is erect and is devoid of any curvature with the micropyle distal and directed away from the placenta |
| c. Hemianatropous ovule | 3. The body of ovule is twisted only half way so that the degree of curvature is at right angle to the funicle |
| d. Campylotropous ovule | 4. The body of ovule becomes curved so that the micropyle and chalaza come to lie on either side of the funicle |
A. a-1, b-2, c-4, d-3
B. a-2, b-1, c-3, d-4
C. a-4, b-1, c-2, d-3
D. a-4, b-3, c-2, d-1
Answer: Option B
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B. Bischofia - Dillenia association
C. Shorea - Lagerstroemia association
D. Mesua - Michelia association
Which of the following react with haemoglobin, forming methemoglobin which will not take up oxygen?
A. Nitrates
B. Nitrites
C. Carbides
D. Oxides
Internally, hydathode shows a group of loosely arranged parenchymatous cells called as
A. Epiderm
B. Epithelium
C. Ampithecium
D. Epithem

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