Examveda
Examveda

Match the following columns:
Column I (Parental species) Column II (Resulting allopolyploid species)
a. Raphanus sativus × Brassica oleracea 1. Nicotiana digluta
b. Nicotianan tabacum × Nicotiana glutinosa 2. Raphanobrassica
c. Triticum aestivum × Secale cerele 3. Gossypium hirsutum
d. Gossypium herbaceum × Gossypium raimondii 4. Triticale

A. a-2, b-1, c-4, d-3

B. a-1, b-2, c-3, d-4

C. a-4, b-3, c-2, d-1

D. a-3, b-4, c-2, d-1

Answer: Option A

Solution(By Examveda Team)

The correct option is a-2, b-1, c-4, d-3.
a) Artificial hybridization of radish (Raphanus sativus) and cabbage (Brassica oleracea) (both 2N = 18) produces a sterile first-generation hybrid with one diploid chromosome set from either parent. Tetraploidization eventually produces a stable, true-breeding hybrid Raphanobrassica.
b) Nicotiana digluta was produced by pollinating a triploid Nicotiana Tabacum plant (2n = 72) with N. glutinosa. N. glutinosa × N. Tabacum = N. digluta.
c) Triticale is a hybrid of wheat (Triticum aestivum) and rye (Secale cerele) first bred in laboratories during the late 19th century in Scotland and Germany. When crossing wheat and rye, wheat is used as the female parent and rye as the male parent (pollen donor).
d) Gossypium hirsutum, also known as upland cotton or Mexican cotton. It is a cross-bred cultivar (Gossypium harbaceum × Gossypium Raimondii) with varying fibre lengths and tolerances to several growing conditions.

This Question Belongs to Agriculture >> Genetics And Plant Breeding

Join The Discussion

Related Questions on Genetics and Plant Breeding