Examveda
Examveda

Mid ordinate calculated by . . . . . . . .

A. $$R\left( {1 - \cos \frac{\phi }{2}} \right)$$

B. $$R\,\operatorname{tan} \frac{\phi }{2}$$

C. $$2R\,\sin \frac{\phi }{2}$$

D. $$R\left( {\sec \frac{\phi }{2} - 1} \right)$$

Answer: Option A


This Question Belongs to Mining Engineering >> Mine Surveying

Join The Discussion

Related Questions on Mine Surveying