No work is done by the system, when a reaction occurs at constant
A. Volume
B. Temperature
C. Pressure
D. None of these
Answer: Option A
Solution (By Examveda Team)
Here work means expansion work since the expansion work ($$W$$) and we know expansion work $$W = \int {} {P_{ext}}dV$$ and since for isochoric process there will be no volume change i..e.., volume remains constant and hence $$dV = 0.$$So, work done $$= 0$$
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