Number of degrees of freedom for a three phase system in equilibrium comprising of three non-reacting chemical species is
A. 2
B. 0
C. 1
D. 3
Answer: Option A
Solution (By Examveda Team)
Given, number of phases $$\left( \emptyset \right) = 3$$Number of non-reacting components $$= 3$$
So, degree of freedom $$ = C - \emptyset + 2 = 3 - 3 + 2 = 2$$
This Question Belongs to Chemical Engineering >> Chemical Engineering Thermodynamics
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