Number of degrees of freedom for a three phase system in equilibrium comprising of three non-reacting chemical species is

A. 2

B. 0

C. 1

D. 3

Answer: Option A

Solution(By Examveda Team)

Given, number of phases $$\left( \emptyset \right) = 3$$
Number of non-reacting components $$= 3$$
So, degree of freedom $$ = C - \emptyset + 2 = 3 - 3 + 2 = 2$$