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Number of degrees of freedom for a three phase system in equilibrium comprising of three non-reacting chemical species is
Answer & Solution
Correct Answer:
Option
A
Given, number of phases $$\left( \emptyset \right) = 3$$
Number of non-reacting components $$= 3$$
So, degree of freedom $$ = C - \emptyset + 2 = 3 - 3 + 2 = 2$$
Number of non-reacting components $$= 3$$
So, degree of freedom $$ = C - \emptyset + 2 = 3 - 3 + 2 = 2$$
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