Examveda

Observe the following Python code?
def a(n):
    if n == 0:
        return 0
    else:
        return n*a(n - 1)
def b(n, tot):
    if n == 0:
        return tot
    else:
        return b(n-2, tot-2)

A. Both a() and b() aren't tail recursive

B. Both a() and b() are tail recursive

C. b() is tail recursive but a() isn't

D. a() is tail recursive but b() isn't

Answer: Option C


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