On a horizontal curve if the pavement is kept horizontal across the alignment, then the pressure on the outer wheels will be

When a pavement is kept horizontal across the alignment i.e. no superelevation is provided, then the pressure on outer tyre is more than that of inner tyre because the centrifugal force acts radially outward and friction will oppose this centrifugal force.

Consider a vehicle travelling on a horizontal curve with no super elevation



Now,



Vehicle is in rotational equilibrium i.e. ∑M0 = 0

Fy + PIx = P0y

(Rightarrow {{
m{P}}_0} = {{
m{P}}_{
m{I}}} + {
m{F}}left( {rac{{
m{y}}}{{
m{x}}}}
ight))

⇒ P0 > PI

Where,

p = centrifugal force on vehicle acting radially outward, F = friction o/w tyre and road acting inward, P0 = outer tyre force, PI = Inner tyre force, and W = weight of vehicle

⇒ Outer tyre pressure is greater than inner tyre pressure.