On a horizontal curve if the pavement is kept horizontal across the alignment, then the pressure on the outer wheels will be
A. more than the pressure on inner wheels
B. less than the pressure on inner wheels
C. equal to the pressure on inner wheels
D. zero
Answer: Option A
This Question Belongs to Civil Engineering >> Highway Engineering
Join The Discussion
Comments ( 1 )
Highway facilities are designed for
A. annual average hourly volume
B. annual average daily traffic
C. thirtieth highest hourly volume
D. peak hourly volume of the year
The provision of traffic signals at intersections
A. reduces right angled and rear end collisions
B. increases right angled and rear end collisions
C. reduces right angled collisions but may increase rear end collisions
D. reduces rear end collisions but may increase right angled collisions
In CBR test the value of CBR is calculated at
A. 2.5 mm penetration only
B. 5.0 mm penetration only
C. 7.5 mm penetration only
D. both 2.5 mm and 5.0 mm penetrations
If aggregate impact value is 20 to 30 percent, then it is classified as
A. exceptionally strong
B. strong
C. satisfactory for road surfacing
D. unsuitable for road surfacing
When a pavement is kept horizontal across the alignment i.e. no superelevation is provided, then the pressure on outer tyre is more than that of inner tyre because the centrifugal force acts radially outward and friction will oppose this centrifugal force.
Consider a vehicle travelling on a horizontal curve with no super elevation
Now,
Vehicle is in rotational equilibrium i.e. ∑M0 = 0
Fy + PIx = P0y
(Rightarrow {{
m{P}}_0} = {{
m{P}}_{
m{I}}} + {
m{F}}left( { rac{{
m{y}}}{{
m{x}}}}
ight))
⇒ P0 > PI
Where,
p = centrifugal force on vehicle acting radially outward, F = friction o/w tyre and road acting inward, P0 = outer tyre force, PI = Inner tyre force, and W = weight of vehicle
⇒ Outer tyre pressure is greater than inner tyre pressure.