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Out of 5 men and 3 women, a committee of three members is to be formed so that it has 1 women, and 2 men. In how many different ways can it be done?

Answer & Solution
Correct Answer: Option D
Required number of ways
$$\eqalign{ & = \left( {{}^3{C_1} \times {}^5{C_2}} \right) \cr & = 3 \times \frac{{5 \times 4}}{{2 \times 1}} \cr & = 30 \cr} $$
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