PA and PB are two tangents from a point P outside the circle with centre O. If A and B are points on the circle such that ∠APB = 142°, then ∠OAB is equal to:
A. 58°
B. 31°
C. 71°
D. 64°
Answer: Option C
Solution (By Examveda Team)
$$\angle {\text{OAB}} = \frac{{{{180}^ \circ } - {{38}^ \circ }}}{2} = {71^ \circ }$$
This Question Belongs to Arithmetic Ability >> Geometry
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In the given figure, ∠ONY = 50° and ∠OMY = 15°. Then the value of the ∠MON is
A. 30°
B. 40°
C. 20°
D. 70°
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