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PA and PB are two tangents from a point P outside the circle with centre O. If A and B are points on the circle such that ∠APB = 142°, then ∠OAB is equal to:

A. 58°

B. 31°

C. 71°

D. 64°

Answer: Option C

Solution(By Examveda Team)

Geometry mcq question image
$$\angle {\text{OAB}} = \frac{{{{180}^ \circ } - {{38}^ \circ }}}{2} = {71^ \circ }$$

This Question Belongs to Arithmetic Ability >> Geometry

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