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Pick up the correct statement from the following:

A. Maximum daily flow = 2 times the average daily flow

B. Maximum daily flow = $$\frac{2}{3}$$ × average daily flow

C. Sewers are designed for minimum permissible velocity at minimum flow

D. All the above

Answer: Option D

Solution (By Examveda Team)

Key Points:

1. Maximum daily flow = 2 times the average daily flow:
This is a standard assumption used in wastewater engineering to account for peak flow conditions.

2. Maximum daily flow = (2/3) × average daily flow:
This is another consideration often used in specific design scenarios, depending on regional practices and flow characteristics.

3. Sewers are designed for minimum permissible velocity at minimum flow:
To prevent sediment deposition, sewers are designed to maintain a minimum velocity, even during low-flow conditions.
This ensures the self-cleansing capability of the sewer system.

Therefore: All the statements are correct, making the correct answer Option D: All the above.

This Question Belongs to Civil Engineering >> Waste Water Engineering

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Comments (1)

  1. CHANDAN VERMA
    CHANDAN VERMA:
    8 months ago

    option B should be minimum daily flow = 2/3 x average daily flow

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