Examveda

Poisson distribution can be expressed by

A. $$P\left( r \right) = \frac{{{e^{ - m}} \cdot {m^r}}}{{r!}}$$

B. $$P\left( r \right) = \frac{{{e^{ - m}}}}{{n + 1}}$$

C. $$P\left( r \right) = \frac{{e \times m}}{n}$$

D. $$P\left( r \right) = \frac{{n + 2}}{m} \times {e^{ - m}}$$

Answer: Option A


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