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PQR is an isosceles triangle such that PQ = QR = 10 cm and ΔPQR = 90°. What is the length of the perpendicular drawn from Q on PR?
Answer & Solution
Correct Answer:
Option
D

$$\eqalign{ & \frac{1}{2} \times 10 \times 10 = \frac{1}{2} \times 10\sqrt 2 \times {\text{QS}} \cr & {\text{QS}} = 5\sqrt 2 \cr} $$
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