Predict the output:
public class Test{
public static void main(String args[]){
try{
String arr[] = new String[10];
arr = null;
arr[0] = "one";
System.out.print(arr[0]);
}catch(Exception ex){
System.out.print("exception");
}catch(NullPointerException nex){
System.out.print("null pointer exception");
}
}
}
public class Test{
public static void main(String args[]){
try{
String arr[] = new String[10];
arr = null;
arr[0] = "one";
System.out.print(arr[0]);
}catch(Exception ex){
System.out.print("exception");
}catch(NullPointerException nex){
System.out.print("null pointer exception");
}
}
}A. "one" is printed.
B. "exception" is printed.
C. "null pointer exception" is printed.
D. Compilation fails saying NullPointerException has already been caught.
E. None of these
Answer: Option D
This Question Belongs to Java Program >> Exceptions
More specified exceptions need to be caught first. Here the general exception is caught first so it will give a compilation error.