Predict the output:
public class Test{
public static void main(String args[]){
try{
String arr[] = new String[10];
arr = null;
arr[0] = "one";
System.out.print(arr[0]);
}catch(Exception ex){
System.out.print("exception");
}catch(NullPointerException nex){
System.out.print("null pointer exception");
}
}
}
public class Test{
public static void main(String args[]){
try{
String arr[] = new String[10];
arr = null;
arr[0] = "one";
System.out.print(arr[0]);
}catch(Exception ex){
System.out.print("exception");
}catch(NullPointerException nex){
System.out.print("null pointer exception");
}
}
}A. "one" is printed.
B. "exception" is printed.
C. "null pointer exception" is printed.
D. Compilation fails saying NullPointerException has already been caught.
E. None of these
Answer: Option D
This Question Belongs to Java Program >> Exceptions
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Comments ( 1 )
A. An error that occurs during runtime
B. An error that occurs during compilation
C. A warning issued by the compiler
D. A type of loop
What is the purpose of the "try" block in exception handling?
A. It catches exceptions and handles them
B. It specifies the exception type
C. It contains the code that might throw an exception
D. It specifies the exception message
In Java, can a method declare multiple exceptions using the "throws" keyword?
A. Only if the method is marked as "static"
B. Yes, a method can declare multiple exceptions separated by commas
C. Only if the exceptions are marked as "final"
D. Only if the method is marked as "static"
More specified exceptions need to be caught first. Here the general exception is caught first so it will give a compilation error.