PVy = constant, holds good for an isentropic process, which is
A. Reversible and isothermal
B. Isothermal and irreversible
C. Reversible and adiabatic
D. Adiabatic and irreversible
Answer: Option C
Solution (By Examveda Team)
We know from second law of thermodynamics for an reversible process $$Tds = \delta Q$$So, $$dS =0$$
When the process is adiabatic.
Hence for a reversible adiabatic process the entropy is constant.
This Question Belongs to Chemical Engineering >> Chemical Engineering Thermodynamics
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