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PVy = constant, holds good for an isentropic process, which is
Answer & Solution
Correct Answer:
Option
C
We know from second law of thermodynamics for an reversible process $$Tds = \delta Q$$
So, $$dS =0$$
When the process is adiabatic.
Hence for a reversible adiabatic process the entropy is constant.
So, $$dS =0$$
When the process is adiabatic.
Hence for a reversible adiabatic process the entropy is constant.
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