Rakesh kumar
Rakesh kumar
5 months ago

A seller bought 2750 Mangoes and 1210 Apples at the same price. He sells in such a way that he can buy 406 Mangoes with the sale of 322 Mangoes and he can buy only 289 Apples with the sale of 391 Apples. Then what is the overall profit percentage made by him?

A. 0%

B. 90%

C. 80%

D. None

Answer: Option A

Solution(By Examveda Team)

Cost of 2750 Mangoes = 1210 Apples
Total cost = 2420 Apples
Given: 406 = 322(100+x/100)
x = 6/23%
Given: 289 = 391(100+y/100)
y = 6/23% loss
Overall profit:
2750 Mangoes*(100+6/23/100) +1210 Apples*(100-6/23/100) = 2420*Apples (100+P/100)
1210 Apples*(100+6/23/100) +1210 Apples*(100-6/23/100) = 2420*Apples (100+P/100)
P = 0%

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Comments ( 4 )

  1. Rakesh Swain
    Rakesh Swain :
    5 days ago

    Cp of 2750 mangos=cp of 1210 apples
    So total cost=5500 ie (2750+2750)
    or =2420 ie 1210+1210
    Buy406m----sell 332
    P%=(sp-cp/cp)*100
    So P%=26%
    Buy 289a------sell 391ahear he or she lost
    L%=-26%
    Overall profit:
    2750 Mangoes*(100+26/100) +1210 Apples*(100-26/100) = 2420*Apples (100+P/100)
    1210 Apples*(100+26/100) +1210 Apples*(100-26/100) = 2420*Apples (100+P/100)
    P = 0%

  2. Janis Laskar
    Janis Laskar :
    3 months ago

    Please explain how did you find total cost?

  3. ABINASHA BISWAL
    ABINASHA BISWAL :
    5 months ago

    Have any other methods??

  4. ABINASHA BISWAL
    ABINASHA BISWAL :
    5 months ago

    Total cost =2420Apples how?? Please explain.

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