Rakesh kumar
5 months ago

# A seller bought 2750 Mangoes and 1210 Apples at the same price. He sells in such a way that he can buy 406 Mangoes with the sale of 322 Mangoes and he can buy only 289 Apples with the sale of 391 Apples. Then what is the overall profit percentage made by him?

A. 0%

B. 90%

C. 80%

D. None

## Solution(By Examveda Team)

Cost of 2750 Mangoes = 1210 Apples
Total cost = 2420 Apples
Given: 406 = 322(100+x/100)
x = 6/23%
Given: 289 = 391(100+y/100)
y = 6/23% loss
Overall profit:
2750 Mangoes*(100+6/23/100) +1210 Apples*(100-6/23/100) = 2420*Apples (100+P/100)
1210 Apples*(100+6/23/100) +1210 Apples*(100-6/23/100) = 2420*Apples (100+P/100)
P = 0%

1. Cp of 2750 mangos=cp of 1210 apples
So total cost=5500 ie (2750+2750)
or =2420 ie 1210+1210
P%=(sp-cp/cp)*100
So P%=26%
Buy 289a------sell 391ahear he or she lost
L%=-26%
Overall profit:
2750 Mangoes*(100+26/100) +1210 Apples*(100-26/100) = 2420*Apples (100+P/100)
1210 Apples*(100+26/100) +1210 Apples*(100-26/100) = 2420*Apples (100+P/100)
P = 0%

2. Please explain how did you find total cost?

3. Have any other methods??

4. Total cost =2420Apples how?? Please explain.