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Reynolds number of a fluid flowing in a circular pipe is...

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Chemical Engineering Basics
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Reynolds number of a fluid flowing in a circular pipe is 10000. What will be the Reynolds number when the fluid velocity is decreased by 30% & the pipe diameter is increased by 30% ?

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Correct Answer: Option A
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Abhilash Konwer
Abhilash Konwer 6 years ago
R={(fluid velocity)*(pipe diameter)}/ kinematic velocity
10000={XY}/Kinematic velocity
Kinematic velocity=XY/10000
Than,
R={(X-30X/100)}*{(Y+30Y/100)}/kinematic velocity
R={(X-30X/100)}*{(Y+30Y/100)}/(XY/10000)
R=(70X*130Y)/XY
R=9100
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