Shannon's channel capacity formula is applicable to the AWGN channel and is given by
A. $$C = B{\log _2}\left( {1 + \frac{S}{N}} \right)$$
B. $$C = B{\log _{10}}\left( {1 + \frac{S}{N}} \right)$$
C. $$C = B{\log _8}\left( {1 + \frac{S}{N}} \right)$$
D. $$C = B{\log _{16}}\left( {1 + \frac{S}{N}} \right)$$
Answer: Option A
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