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If $${\text{5}}\sqrt 5 \times {{\text{5}}^3} \div {{\text{5}}^{ - \frac{3}{2}}}{\text{ = }}{{\text{5}}^{a + 2}}{\text{,}}$$ then the value of a is = ?
Answer & Solution
Correct Answer:
Option
A
$$\eqalign{
& {\text{5}}\sqrt 5 \times {{\text{5}}^3} \div {{\text{5}}^{ - \frac{3}{2}}}{\text{ = }}{{\text{5}}^{a + 2}} \cr
& \Rightarrow {{\text{5}}^1} \times {5^{\frac{1}{2}}} \times {{\text{5}}^3} \div {{\text{5}}^{ - \frac{3}{2}}}{\text{ = }}{{\text{5}}^{a + 2}} \cr
& \Rightarrow {5^{1 + \frac{1}{2} + 3 - \left( { - \frac{3}{2}} \right)}} = {5^{a + 2}} \cr
& \Rightarrow {5^{1 + \frac{1}{2} + 3 + \frac{3}{2}}} = {5^{a + 2}} \cr
& \Rightarrow {5^6} = {5^{a + 2}} \cr
& \Rightarrow a + 2 = 6 \cr
& \Rightarrow a = 4 \cr} $$
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