Starting from his house one day, a student walks at a speed of 2.5 km/hr and reaches his school 6 minutes late. Next day at the same time he increases his speed by 1 km/hr and reaches the school 6 minutes early. How for is the school from his house ?
A. 1 km
B. 1½ km
C. 1¾ km
D. 2 km
Answer: Option C
Solution (By Examveda Team)
Let the distance be x kmDifference in timing
T1 = x/2.5
T2 = x/3.5 and
T1 - T2 = 12 mins ( 6+6=12) i.e.12/60 hrs
(12/60) = x/2.5 - x/3.5
1/5 = 1x/(2.5)(3.5)
1/5 = 1x/8.75
8.75 = 5x ( cross multiplication)
x = 1.75 1¾ km
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