Starting from x0 = 1, one step of Newton-Raphson method in solving the equation x3 + 3x - 7 = 0 gives the next value (x1) as
A. x1 = 0.5
B. x1 = 1.406
C. x1 = 1.5
D. x1 = 2
Answer: Option C
A. x1 = 0.5
B. x1 = 1.406
C. x1 = 1.5
D. x1 = 2
Answer: Option C
Roots of the algebraic equation x3 + x2 + x + 1 = 0 are
A. (+1, +j, -j)
B. (+1, -1, +1)
C. (0, 0, 0)
D. (-1, +j. -j)
A. Only I
B. Only II
C. Both I and II
D. Neither I nor II
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