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Suppose 4a = 5, 5b = 6, 6c = 7, 7d = 8, then the value of abcd is = ?
Answer & Solution
Correct Answer:
Option
B
$$\eqalign{
& 8 = {7^d} \cr
& \,\,\,\,\,\, = {\left( {{6^c}} \right)^d} \cr
& \,\,\,\,\,\, = {\left( {{5^b}} \right)^{cd}} \cr
& \,\,\,\,\,\, = {5^{bcd}} \cr
& \,\,\,\,\,\, = {\left( {{4^a}} \right)^{bcd}} \cr
& \,\,\,\,\,\, = {4^{abcd}} \cr
& \Rightarrow {4^{abcd}} = 8 \cr
& \Rightarrow {\left( {{2^2}} \right)^{abcd}} = {2^3} \cr
& \Rightarrow 2abcd = 3 \cr
& \Rightarrow abcd = \frac{3}{2} \cr} $$
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