Suppose we uniformly and randomly select a permutation from the 20! permutations of 1, 2, 3 ...., 20. What is the probability that 2 appears at an earlier position that any other even number in the selected permutation?
A. $$\frac{1}{2}$$
B. $$\frac{1}{{10}}$$
C. $$\frac{{9!}}{{20!}}$$
D. None of these
Answer: Option D
This Question Belongs to Engineering Maths >> Probability And Statistics
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A. E(XY) = E(X) E(Y)
B. Cov (X, Y) = 0
C. Var (X + Y) = Var (X) + Var (Y)
D. E(X2Y2) = (E(X))2 (E(Y))2
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