The 3rd and 8th term of an arithmetic progression are -13 and 2 respectively. What is the 14th term?
A. 23
B. 17
C. 20
D. 26
Answer: Option C
Solution(By Examveda Team)
Let the first term of an AP = a and the common difference = d3rd term of AP = A3 = a + 2d = -13 ...... (1)
8th term = A8 = a + 7d = 2 ...... (2)
Subtracting equation (1) from (2), we get :
⇒ 7d - 2d = 2 - (-13)
⇒ 5d = 15
⇒ d = $$\frac{{15}}{5}$$ = 3
Substituting it in equation (2)
⇒ a = 2 - 7(3) = 2 - 21 = -19
∴ 14th term = A14 = a + 13d
= -19 + 13(3)
= -19 + 39
= 20
Related Questions on Progressions
Find the first term of an AP whose 8th and 12th terms are respectively 39 and 59.
A. 5
B. 6
C. 4
D. 3
E. 7
The sum of the first 16 terms of an AP whose first term and third term are 5 and 15 respectively is
A. 600
B. 765
C. 640
D. 680
E. 690
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