Examveda
Examveda

The 3rd and 8th term of an arithmetic progression are -13 and 2 respectively. What is the 14th term?

A. 23

B. 17

C. 20

D. 26

Answer: Option C

Solution(By Examveda Team)

Let the first term of an AP = a and the common difference = d
3rd term of AP = A3 = a + 2d = -13 ...... (1)
8th term = A8 = a + 7d = 2 ...... (2)
Subtracting equation (1) from (2), we get :
⇒ 7d - 2d = 2 - (-13)
⇒ 5d = 15
⇒ d = $$\frac{{15}}{5}$$ = 3
Substituting it in equation (2)
⇒ a = 2 - 7(3) = 2 - 21 = -19
∴ 14th term = A14 = a + 13d
= -19 + 13(3)
= -19 + 39
= 20

This Question Belongs to Arithmetic Ability >> Progressions

Join The Discussion

Related Questions on Progressions