The activity of an ideal gas is numerically __________ its pressure.
A. More than
B. Less than
C. Equal to
D. Data insufficient, can't be predicted
Answer: Option C
Solution (By Examveda Team)
Activity $$\left( a \right)$$ of a pure ideal gas is defined as:$$a = \frac{{{\text{fugacity at an temperature and pressure of interest}}}}{{{\text{fugacity at same temperature and standard pressure }}}}$$
usually the, standard pressure $$=$$ 1 atm and for ideal gas fugacity at a temperature and pressure $$=$$ pressure at that conditions
So, $$a=P$$
This Question Belongs to Chemical Engineering >> Chemical Engineering Thermodynamics
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