The angle between the minute hand and the hour hand of a clock when the time is 4:20, is:
A. 0º
B. 10º
C. 5º
D. 20º
Answer: Option B
Solution(By Examveda Team)
$$\eqalign{ & {\text{Angle}}\,{\text{traced}}\,{\text{by}}\,{\text{hour}}\,{\text{hand}}\,{\text{in}}\,\frac{{13}}{3}\,{\text{hrs}} \cr & = {\left( {\frac{{360}}{{12}} \times \frac{{13}}{3}} \right)^ \circ } = {130^ \circ } \cr & {\text{Angle}}\,{\text{traced}}\,{\text{by}}\,{\text{min}}{\text{.}}\,{\text{hand}}\,{\text{in}}\,{\text{20}}\,{\text{min}} \cr & = {\left( {\frac{{360}}{{60}} \times 20} \right)^ \circ } = {120^ \circ } \cr & \therefore {\text{Required}}\,{\text{angle}} \cr & = {\left( {130 - 120} \right)^ \circ } \cr & = {10^ \circ } \cr} $$Join The Discussion
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Related Questions on Clock
The reflex angle between the hands of a clock at 10.25 is:
A. 180º
B. $${\text{192}}{\frac{1}{2}^ \circ }$$
C. 195º
D. $${\text{197}}{\frac{1}{2}^ \circ }$$
A clock is started at noon. By 10 minutes past 5, the hour hand has turned through:
A. 145º
B. 150º
C. 155º
D. 160º
A. $$59\frac{7}{{12}}$$ min. past 3
B. 4 p.m.
C. $$58\frac{7}{{11}}$$ min. past 3
D. $$2\frac{3}{{11}}$$ min. past 4
4.20 = 4 hour 20 min = 260 min
260/60 hours = 13/3 hours
from where do we get this 13/3 hrs