The compressibility factor of a gas is given by (where, V1 = actual volume of the gas V2 = gas volume predicted by ideal gas law)
A. $$\frac{{{{\text{V}}_1}}}{{{{\text{V}}_2}}}$$
B. $$\frac{{{{\text{V}}_2}}}{{{{\text{V}}_1}}}$$
C. V1 - V2
D. V1 × V2
Answer: Option A
Solution (By Examveda Team)
The compressibility factor is given by $$Z = \frac{{P{V_1}}}{{RT}}.$$ If at the same temperature and pressure if the same gas exists as ideal gas than we can write:\[\begin{array}{l} Z = 1 = \frac{{P{V_2}}}{{RT}} \Rightarrow \frac{{RT}}{P} = {V_2}\\ {\rm{So, }}\,\,Z = \frac{{{V_1}}}{{{V_2}}}. \end{array}\]
This Question Belongs to Chemical Engineering >> Chemical Engineering Thermodynamics
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