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Differential Equations
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The differential equation $$\frac{{{{\text{d}}^2}{\text{y}}}}{{{\text{d}}{{\text{x}}^2}}} + 16{\text{y}} = 0$$    for y(x) with the two boundary conditions $${\left. {\frac{{{\text{dy}}}}{{{\text{dx}}}}} \right|_{{\text{x}} = 0}} = 1$$   and $${\left. {\frac{{{\text{dy}}}}{{{\text{dx}}}}} \right|_{{\text{x}} = \frac{\pi }{2}}} = - 1$$   has

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Correct Answer: Option A
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