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The effective inductance across 'AB' of the infinite ladder shown in the figure below is-
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A. $$\left( {1 + \sqrt 3 } \right){\text{L}}$$

B. $$\frac{{\left( {1 + \sqrt 5 } \right){\text{L}}}}{2}$$

C. $$\left( {1 + \sqrt 5 } \right){\text{L}}$$

D. $$\left( {1 + \sqrt 7 } \right){\text{L}}$$

Answer: Option B


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