The effective inductance across 'AB' of the infinite ladder shown in the figure below is-

A. $$\left( {1 + \sqrt 3 } \right){\text{L}}$$
B. $$\frac{{\left( {1 + \sqrt 5 } \right){\text{L}}}}{2}$$
C. $$\left( {1 + \sqrt 5 } \right){\text{L}}$$
D. $$\left( {1 + \sqrt 7 } \right){\text{L}}$$
Answer: Option B

Join The Discussion