The efficiency of the Carnot cycle is (where T1 and T2 = Highest and lowest temperature during the cycle)
A. $$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}} - 1$$
B. $$1 - \frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}}$$
C. $$1 - \frac{{{{\text{T}}_2}}}{{{{\text{T}}_1}}}$$
D. $$1 + \frac{{{{\text{T}}_2}}}{{{{\text{T}}_1}}}$$
Answer: Option C
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