The efficiency of the Carnot cycle is (where T1 and T2 = Highest and lowest temperature during the cycle)

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This question belongs to Mechanical Engineering Engineering Thermodynamics

Engineering Thermodynamics

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The efficiency of the Carnot cycle is (where T₁ and T₂ = Highest and lowest temperature during the cycle)

A) $$\frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}} - 1$$ B) $$1 - \frac{{{{\text{T}}_1}}}{{{{\text{T}}_2}}}$$ C) $$1 - \frac{{{{\text{T}}_2}}}{{{{\text{T}}_1}}}$$ D) $$1 + \frac{{{{\text{T}}_2}}}{{{{\text{T}}_1}}}$$

Answer & Solution

Correct Answer: Option C

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