The electric field on the surface of a perfect conductor is 2 V/m. The conductor is immersed in water with ∈ = 80 ∈0. The surface charge density on the conductor is $$\left( { \in = \frac{{{{10}^{ - 9}}}}{{36\pi }}} \right){\text{F/m}}$$
A. 0 C/m2
B. 2 C/m2
C. 1.8 × 10-11 C/m2
D. 1.41 × 10-9 C/m2
Answer: Option D
This Question Belongs to Electronics And Communications Engineering >> Electromagnetic Field Theory
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