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The energies E1 and E2 of the two radiations are 25eV and 50eV respectively. The relation between their wavelengths i.e. λ1 and λ2 will be . . . . . . . .

A. $${\lambda _1} = \left( {\frac{1}{2}} \right){\lambda _2}$$

B. λ1 = λ2

C. λ1 = 2λ2

D. λ1 = 4λ2

Answer: Option C

Solution (By Examveda Team)

We are given two radiations with energies E1 = 25 eV and E2 = 50 eV, and we need to determine how their wavelengths λ1 and λ2 are related.
The energy of radiation is inversely proportional to its wavelength, as described by the equation:
E = h * c / λ
Where:
E is the energy of the radiation,
h is Planck's constant,
c is the speed of light, and
λ is the wavelength.
Since energy and wavelength are inversely proportional, we can express the ratio of the wavelengths in terms of the energies:
λ1 / λ2 = E2 / E1
Substituting the values for the energies:
λ1 / λ2 = 50 / 25 = 2
This means that the wavelength λ1 is twice the wavelength λ2. Hence, λ1 = 2λ2.
Thus, the correct answer is Option C.

This Question Belongs to Physics GK Chapter Wise >> Light

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Comments (1)

  1. Dipankar Patra
    Dipankar Patra:
    1 year ago


    The energies E1 and E2 of the two radiations are 25eV and 50eV respectively. The relation between their wavelengths i.e. λ1 and λ2 will be

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