The energy $$E\left( {\overrightarrow {\bf{k}} } \right)$$ of electrons of wave vector $$\overrightarrow {\bf{k}} $$ in a solid is given by $$E\left( {\overrightarrow {\bf{k}} } \right) = A{k^2} + B{k^4},$$ where A and B are constants. The effective mass of the electron at $$\left| {\overrightarrow {\bf{k}} } \right| = {k_0}$$ is
A. $$Ak_0^2$$
B. $$\frac{{{\hbar ^2}}}{{2A}}$$
C. $$\frac{{{\hbar ^2}}}{{2A + 12Bk_0^2}}$$
D. $$\frac{{{\hbar ^2}}}{{Bk_0^2}}$$
Answer: Option C
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