Examveda

The energy $$E\left( {\overrightarrow {\bf{k}} } \right)$$  of electrons of wave vector $$\overrightarrow {\bf{k}} $$ in a solid is given by $$E\left( {\overrightarrow {\bf{k}} } \right) = A{k^2} + B{k^4},$$    where A and B are constants. The effective mass of the electron at $$\left| {\overrightarrow {\bf{k}} } \right| = {k_0}$$  is

A. $$Ak_0^2$$

B. $$\frac{{{\hbar ^2}}}{{2A}}$$

C. $$\frac{{{\hbar ^2}}}{{2A + 12Bk_0^2}}$$

D. $$\frac{{{\hbar ^2}}}{{Bk_0^2}}$$

Answer: Option C


This Question Belongs to Engineering Physics >> Solid State Physics

Join The Discussion

Related Questions on Solid State Physics

In a cubic crystal, atoms of mass M1 lie on one set of planes and atoms of mass M2 lie on planes interleaved between those of the first set. If C is the forte constant between nearest neighbour planes, the frequency of lattice vibrations for the optical phonon branch with wave vector k = 0 is

A. $$\sqrt {2C\left( {\frac{1}{{{M_1}}} + \frac{1}{{{M_2}}}} \right)} $$

B. $$\sqrt {C\left( {\frac{1}{{2{M_1}}} + \frac{1}{{{M_2}}}} \right)} $$

C. $$\sqrt {C\left( {\frac{1}{{{M_1}}} + \frac{1}{{2{M_2}}}} \right)} $$

D. zero